I miss ModDB...

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Posted by mrl515 on May 3rd, 2011

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You know I was going to, but then I realized how many dots there actually were, so I gave up. Can I haz Cookie anyway? :)

It's all yours! Check my images ;)

'tis easy, it is just the fibonacci sequence up to the 20'th variable and back down again 3 times.

3 x 5 x 11 x 41 = 6765 since the nth term is 20

since n = 20 therefore

3x( 6765 x 2) = about 40590 dots

3 because of 3 sets of sequences

2 because of the Fibonacci sequence occurring "twice" as it goes up and down

aren't I a clever boy

Cookie please

Yikes this question caught me out because it does not go down to "20 and 1" three times.

The nth term = 20 in the first sequence therefore:

n=20

n2=19 (I am not timesing n here)

n3=18

18 : 2584 = 23 x 17 x 19

19 : 4181 = 37 x 113

20 : 6765 = 3 x 5 x 11 x 41

So 2584+4181+6765 = 13530 precisely

no need to count, just some knowledge of numerical sequences is all you need

w..w...wait i made a mistake here.

The answer is 1200

i am an idiot

Congrats, only Captain Mazerolle won since he asked nicely, sorry :)