I miss ModDB...

Posted by mrl515 on May 3rd, 2011

A cookie to whoever is lazy enough to count all the dots ;)

.
..
...
....
.....
......
.......
........
.........
..........
...........
............
.............
..............
...............
................
.................
..................
...................
....................
...................
..................
.................
................
...............
..............
.............
............
..........
.........
........
.......
......
.....
....
...
..

..
...
....
.....
......
.......
........
.........
..........
...........
............
.............
..............
...............
................
.................
..................
...................
....................
...................
..................
.................
................
...............
..............
.............
............
..........
.........
........
.......
......
.....
....
...
..
.
..
...
....
.....
......
.......
........
.........
..........
...........
............
.............
..............
...............
................
.................
..................
...................
....................
...................
..................
.................
................
...............
..............
.............
............
..........
.........
........
.......
......
.....
....
...
..
.

Post comment Comments
CaptainMazerolle
CaptainMazerolle May 25 2011, 10:58am says:

You know I was going to, but then I realized how many dots there actually were, so I gave up. Can I haz Cookie anyway? :)

+2 votes     reply to comment
mrl515
mrl515 May 26 2011, 10:57am replied:

It's all yours! Check my images ;)

+2 votes     reply to comment
TheTriangulum
TheTriangulum Apr 25 2012, 3:01pm says:

'tis easy, it is just the fibonacci sequence up to the 20'th variable and back down again 3 times.
3 x 5 x 11 x 41 = 6765 since the nth term is 20
since n = 20 therefore
3x( 6765 x 2) = about 40590 dots

3 because of 3 sets of sequences
2 because of the Fibonacci sequence occurring "twice" as it goes up and down

aren't I a clever boy

Cookie please

+2 votes     reply to comment
TheTriangulum
TheTriangulum Apr 25 2012, 3:11pm replied:

Yikes this question caught me out because it does not go down to "20 and 1" three times.
The nth term = 20 in the first sequence therefore:
n=20
n2=19 (I am not timesing n here)
n3=18

18 : 2584 = 23 x 17 x 19
19 : 4181 = 37 x 113
20 : 6765 = 3 x 5 x 11 x 41

So 2584+4181+6765 = 13530 precisely

no need to count, just some knowledge of numerical sequences is all you need

+2 votes     reply to comment
TheTriangulum
TheTriangulum Apr 25 2012, 3:30pm says:

w..w...wait i made a mistake here.
The answer is 1200

+1 vote     reply to comment
TheTriangulum
TheTriangulum Apr 25 2012, 7:10pm replied:

i am an idiot

+1 vote     reply to comment
mrl515
mrl515 May 24 2012, 4:42pm replied:

Congrats, only Captain Mazerolle won since he asked nicely, sorry :)

+1 vote     reply to comment
Post a Comment
click to sign in

You are not logged in, your comment will be anonymous unless you join the community today (totally free - or sign in with your social account on the right) which we encourage all contributors to do.

2000 characters limit; HTML formatting and smileys are not supported - text only

Level
Avatar
Avatar
Offline Since
Aug 23, 2014
Country
United States United States
Gender
Male
Member Watch
Track this member
Blog
Browse
Blogs
Report Abuse
Report article